9y^2+63y=0

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Solution for 9y^2+63y=0 equation: 



9y^2+63y=0

a = 9; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·9·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*9}=\frac{-126}{18}
=-7
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*9}=\frac{0}{18}
=0
$

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